That would be D
the first 3 = -12x + 24
bur D = -12x - 24
11x + 2 = 13x, 9x - 4 = 5x, 5x + 13x = 18x
AB=√{(6+3)²+(6-2)^2}=√(81+16)=√(97)
BC=√((7-6)²+(-1-6)²)=√(50)=5√2
AC=√((7+3)²+(-1-1)²)=2√(26)
Perimeter=AB+BC+AC=√97+5√2+2√(26)
This is the future value quadrupled in t years at an annual interest rate of 6.5% compounded daily. We need to find t.
1*(1+0.065/365)^(365t)t=4
take log on both sides,
365t(log(1+0.065/365)=log(4)
=>
365t=log(4)/log(1+0.065/365)
t=(log(4)/log(1+0.065/365))/365
=(1.38629/.000178066)/365
=21.33 years
Check with the rule of 69, applicable to continuous compounding (an approximation to current problem) to double money, it take 69/interest rate in % years.
=69/6.5
=10.62 years
To double twice (quadruple), it takes twice 10.62
=21.24 years, not that far from 21.33 that we got earlier.