Answer:
Step-by-step explanation:
Remark
The formula for this is
Heat = m * c * Δt
Givens
Heat = unknown
m = 200 grams
c = 4.184 Joules / grams oC
Δt = the change in temperature = 35.7 - 22.3 = 13.4
Solution
Heat = 200 * 4.184 * 13.4
Heat = 11213 Joules
Heat = 11.2 Kj
It's hard to get the correct number of sig digs because the 200 is not qualified in any way.
Part 2.
This can really puzzle you until you know that heat given up = the heat taken on. The heat taken on was 11.2 Kj. The Butane lighter must have given that heat on.
Heat of Combustion = Heat Given Up / Number grams burned.
Heat of Combustion = 11.2 Kj / 0.23 grams
Heat of Combustion = 48.8 Kj / gram
Answer:
2 seconds
Step-by-step explanation:
The error is in the second step they subtracted 3 from both sides but it was a 3x, which you can not do.
Correction.
9x+18+3x=1
12x+18=1
12x=-17
x=-17/12
Answer:
y = -13x + 4
Step-by-step explanation:
You want to put it in the form y = mx + b where m is the slope and b is the y-intercept (For example, in the equation y = 2x + 3 the slope is 2 and the y-intercept is 3)
Since the slope is -13, m = -13.
Since the y-intercept is 4, b = 4.
This means the equation is y = -13x + 4
Yes based on ja 82 and it can be added
