All categories

2 years ago

C3H8 + xO2 > 3CO2 + yH2O which value of x and y balance the equations

Chemistry

1 answer:

Gelneren [198K]2 years ago

8 0

Answer:

x = 5 and y =4

Explanation:

An alkane is a hydrocarbon of general molecular formula CnH2n+2. The general formula for balancing the combustion equation of any alkane is;

CnH2n+2 + 3n+1/2O2 ------> nCO2 + (n+1) H2O

Where n is the number of carbon atoms in the alkane.

In C3H8 , n=3 so;

C3H2(3)+2 + 3(3)+1/2O2 ------> 3CO2 + (3+1) H2O

Then;

C3H8 + 5O2 ------> 3CO2 + 4H2O

Therefore;

x = 5 and y =4

You might be interested in

Would you rather play warfare of play fortnight

kakasveta [241]

Answer:

i rather just sit on a guys lap and watch him play than me playing cause those games mad frustrating

Explanation:

5 0

2 years ago

Hi! I produce proteins inside the cell. What am I?

Arturiano [62]

Answer:

ribosome is the cell

Explanation:

hsduuejxkwnckwnirj

6 0

2 years ago

Read 2 more answers

2 HI(g) ⇄ H2(g) + I2(g) Kc = 0.0156 at 400ºC 0.550 moles of HI are placed in a 2.00 L container and the system is allowed to rea

Alex_Xolod [135]

Answer: The concentration of hydrogen gas at equilibrium is 0.0275 M

Explanation:

Molarity is calculated by using the equation:

$\text{Molarity}=\frac{\text{Number of moles}}{\text{Volume of solution (in L)}}$

Moles of HI = 0.550 moles

Volume of container = 2.00 L

$\text{Initial concentration of HI}=\frac{0.550}{2}=0.275M$

For the given chemical equation:

$2HI(g)\rightleftharpoons H_2(g)+I_2(g)$

Initial: 0.275

At eqllm: 0.275-2x x x

The expression of $K_c$ for above equation follows:

$K_c=\frac{[H_2][I_2]}{[HI]^2}$

We are given:

$K_c=0.0156$

Putting values in above expression, we get:

$0.0156=\frac{x\times x}{(0.275-2x)^2}\\\\x=-0.0458,0.0275$

Neglecting the negative value of 'x' because concentration cannot be negative

So, equilibrium concentration of hydrogen gas = x = 0.0275 M

Hence, the concentration of hydrogen gas at equilibrium is 0.0275 M

4 0

2 years ago

True or false. An excited state is less stable than a ground state

vladimir2022 [97]

Answer: True!

Explanation: As electrons that are excited move between energy levels, they emit lots and lots of energy, in fact way more energy than ground state electrons (electrons that move within the same energy level) do, thus, making them more unstable.

3 0

2 years ago

3- Fully folded proteins typically have polar side chains on their surfaces, where electrostatic attractions and hydrogen bonds

Elden [556K]

Answer:

Option C= A hydrogen bond formed between a polar side chain and a hydrophobic side chain.

Explanation:

All three given options a, b and d have common mechanism to accommodate the polar amino acid.

A= A hydrogen bond forms between two polar side chains.

B= A hydrogen bond from between a polar side chain and protein back bone.

D = hydrogen bond form between polar side chains and a buried water molecules.

All these are use to accommodate the polar amino acid.

While option C is not used. which is:

A hydrogen bond formed between a polar side chain and a hydrophobic side chain.

5 0

2 years ago