The answer is <span>C. 210 mi
</span>
The velocity (v) is distance (d) divided by time (t):
v = d/t
v = 60 mph
t = 3 1/2 h = 3.5 h
d = ?
d = v * t
d = 60 * 3.5 = 210 mi
Since the problem is 2x^2-5xy-y^3 we first have to plug in what the x and y stands for, once you do that your problem should look like this:
2(-3)^2- 5(-3)(-2)- (-2)^3
Now take the parentheses away and when you do that your signs change.
2x3^2-5x(-3)x(-2)-(-2)^3
do it again with -5x(-3)x(-2)
2x3^2-30-(-2)^3
now do this with (-2)^3
2x3^2-30-(-8)
Now evaluate the power
3^2 becomes 9
2x9-30-(-8)
then change -(-8) to a positive since two negatives make a positive
2x9-30+8
Now multiply the numbers 2x9
18-30+8
Then do 18-30 which equals -12 then add 8
Now you are left with your answer:
<u>-4</u>
Hope this helps! :3
The answer is 4 1/6 because 4/1 + 1/6= 25/6 = 4 1/6.
Answer:
495 meter²
Step-by-step explanation:
In the given kite QRST,
PQ = PS = 15 meter
QR = 17 meter
We have to find the area of the kite.
Since kite is in the form of a rhombus.
and rhombus is = (Diagonal QS) × (Diagonal RT)
In Δ QRP,
17² = 15² + RP²
= √64 = 8 meters.
So RT = RP + PT = 8 + 25 = 33 meter.
Now area of kite = (30) (33) = 495 meter²
Answer:
9 3/5
Step-by-step explanation:
96/10 = 48/5