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2 years ago

How do I solve this?

Mathematics

1 answer:

bulgar [2K]2 years ago

5 0

Answer:

I think you should try the method of substitution???

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Which equation has roots of 3plus or minus sqare rt 2?

vichka [17]

Answer:

Option D is correct.

The equation with roots 3 plus or minus square root 2 is x² - 6x + 7

Step-by-step explanation:

The roots of the unknown equation are

3 ± √2, that is, (3 + √2) and (3 - √2)

The equation can then be reconstructed by writing these roots as the solutions of the quadratic equation

x = (3 + √2) or x = (3 - √2)

The equation is this

[x - (3 + √2)] × [x - (3 - √2)]

(x - 3 - √2) × (x - 3 + √2)

x(x - 3 + √2) - 3(x - 3 + √2) - √2(x - 3 + √2)

= x² - 3x + x√2 - 3x + 9 - 3√2 - x√2 + 3√2 - 2

Collecting like terms

= x² - 3x - 3x + x√2 - x√2 - 3√2 + 3√2 + 9 - 2

= x² - 6x + 7

Hope this Helps!!!

6 0

3 years ago

A computer virus is trying to corrupt two files. The first file will be corrupted with probability 0.4. Independently of it, the

Ksivusya [100]

Answer:

$P(X = 0) = 0.42$

$P(X = 1) = 0.46$

$P(X = 2) = 0.12$

Step-by-step explanation:

We have these following probabilities:

40% probability that the first file is corrupted. So 60% probability that the first file is not corrupted.

30% probability that the second file is corrupted. So 70% probability that the second file is not corrupted.

Probability mass function

Probability of each outcome(0, 1 and 2 files corrupted).

No files corrupted:

60% probability that the first file is not corrupted.

70% probability that the second file is not corrupted.

$P(X = 0) = 0.6*0.7 = 0.42$

One file corrupted:

First one corrupted, second no.

40% probability that the first file is corrupted.

70% probability that the second file is not corrupted.

First one ok, second one corrupted.

60% probability that the first file is not corrupted.

30% probability that the second file is corrupted.

$P(X = 1) = 0.4*0.7 + 0.6*0.3 = 0.46$

Two files corrupted:

40% probability that the first file is corrupted.

30% probability that the second file is corrupted.

$P(X = 2) = 0.4*0.3 = 0.12$

8 0

2 years ago

Write a multiplication expression using the following clues:

Vedmedyk [2.9K]

5
8

6 or 7
Just taking a guess

3 0

2 years ago

Merritt is driving to mount Shasta. On her map, she is a distance of 7.75 inches away. The scale on the map is .5 inch = 50 Mile

amm1812

193.75 miles cause 7.75 * .5 = 3.875 and 3.875* 50 = 193.75

6 0

2 years ago

If -1 is one of the zeroes of py 3x^3-5x^2-11x-3 find other zeroes

katrin2010 [14]

Given:

The function is:

$y=3x^3-5x^2-11x-3$

It is given that -1 is a zero of the given function.

To find:

The other zeroes of the given function.

Solution:

If c is a zero of a polynomial P(x), then (x-c) is a factor of the polynomial.

It is given that -1 is a zero of the given function. So, $(x+1)$ is a factor of the given function.

We have,

$y=3x^3-5x^2-11x-3$

Split the middle terms in such a way so that we get (x+1) as a factor.

$y=3x^3+3x^2-8x^2-8x-3x-3$

$y=3x^2(x+1)-8x(x+1)-3(x+1)$

$y=(x+1)(3x^2-8x-3)$

Again splitting the middle term, we get

$y=(x+1)(3x^2-9x+x-3)$

$y=(x+1)(3x(x-3)+1(x-3))$

$y=(x+1)(3x+1)(x-3)$

For zeroes, $y=0$ .

$(x+1)(3x+1)(x-3)=0$

$(x+1)=0$ and $3x+1=0$ and $x-3=0$

$x=-1$ and $x=-\dfrac{1}{3}$ and $x=3$

Therefore, the other two zeroes of the given function are $-\dfrac{1}{3}$ and $3$ .

3 0

2 years ago