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There are 50 deer in a particular forest. The population is increasing at a rate of 15% per year. Which exponential growth function represents
the number of deer y in that forest after x months? Round to the nearest thousandth.
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dribeiro
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Answer:
The expression that represents the number of deer in the forest is
y(x) = 50*(1.013)^x
Step-by-step explanation:
Assuming that the number of deer is "y" and the number of months is "x", then after the first month the number of deer is:
y(1) = 50*(1+ 0.15/12) = 50*(1.0125) = 50.625
y(2) = y(1)*(1.0125) = y(0)*(1.0125)² =51.258
y(3) = y(2)*(1.0125) = y(0)*(1.0125)³ = 51.898
This keeps going as the time goes on, so we can model this growth with the equation:
y(x) = 50*(1 - 0.15/12)^(x)
y(x) = 50*(1.013)^x
<h3>Answer: Choice A) x+14</h3>
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Work Shown:
(f-g)(x) = f(x) - g(x)
(f-g)(x) = (f(x)) - (g(x))
(f-g)(x) = (3x+10) - (2x-4)
(f-g)(x) = 3x+10 - 2x+4
(f-g)(x) = (3x-2x) + (10+4)
(f-g)(x) = x+14
<span>The graph of g is the graph of f translated to the left 3 units and down 7 units .</span>
Answer:
your answer is 0 because it's a horizontal line
