They have to have a positive charge and negative so then thats what u get
Initial volume of mercury is
V = 0.1 cm³
The temperature rise is 35 - 5 = 30 ⁰C = 30 ⁰K.
Because the coefficient of volume expansion is 1.8x10⁻⁴ 1/K, the change in volume of the mercury is
ΔV = (1.8x10⁻⁴ 1/K)*(30 ⁰K)(0.1 cm³) = 5.4x10⁻⁴ cm³
The cross sectional area of the tube is
A = 0.012 mm² = (0.012x10⁻² cm²).
Therefore the rise of mercury in the tube is
h = ΔV/A
= (5.4x10⁻⁴ cm³)/(0.012x10⁻² cm²)
= 4.5 cm
Answer: 4.5 cm
The answer would be 46.482 because you multiply 18.3 by 2.54 because for every inch you get 2.54 centimeters
Our data are,
State 1:
State 2:
We know as well that 
To find the mass we apply the ideal gas formula, which is given by
Re-arrange for m,
Because of the pressure, temperature and volume ratio of state 1 and 2, we have to
Replacing,
For conservative energy we have, (Cv = 0.718)
The magnitude<span> of a </span>velocity<span> vector is </span>called<span> speed. Supposethat a wind is blowing in from the direction at a speed of 50 km/h. (This meansthat the direction from which the wind blows is west of the northerly direction.) Apilot is steering a plane in the direction at an airspeed (speed in still air) of250 km/h
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