63,889 rounded to the nearest hundred is 63,900
I think b not sure it’s the only one that makes sense
Given - Taisha has a general goal is to burn the 280 calories.
she is varies by the 25 calories.
Find out the maximum and minimum of calories burn by the taisha.
To proof -
let us assume that the calories burn by the taisha be x.
as given the calories are varies by the 25 calories.
then the maximum calories equation becomes
x-25 = 280
x = 280 + 25
x = 305
the maximum calories burn by the taisha is 305 calories.
minimum calories equationbecomes
x + 25 = 280
x = 255
The minmum calories burn by the taisha is 255 calories.
Hence proved
We always start from right side in order of operation in any equation
we can set up equation as
step-1:
x divided by three
we can write as
step-2:
six more than x divided by three
so, we get
step-3:
y is six more than x divided by three
so, we get
and this is in y=mx+b form
so, we have
...............Answer
