6^2 + 8^2 = 36 + 64 = 100
sqrt(100) = 10 m/s northwest
Answer:
3.44 metres
Explanation:
To determine the vector sum of the displacements Δd1 = 2.4 m [32° S of W]; Δd2 = 1.6 m [S]; and Δd3 = 4.9 m [27° S of E], resolve the given parameters into x - component and y - component.
Resolving into x - component
- 2.4cos32 + 4.9cos27 = 2.3306
Resolving into y - component
- 2.4sin32 - 4.9sin27 - 1.6 = - 2.553
The vector sum of the displacement will be
Sqrt( 2.3^2 + 2.6^2) =
Sqrt ( 11.81)
3.44 m
Therefore, the vector sum of the displacements is 3.44 metres
An object with volume greater than it mass. to account less density and thus it will float
Answer:
At most 2 hours
Explanation:
According to my research of various health departments it is said that cooked food should not be left out in room temperature for more than 2 hours, assuming that room temperature is between 40°F and 140°F. This is because after 2 hours bacteria starts to grow at an increased rate and can have various health effects on the person consuming the food. Therefore food is best wrapped and placed in the refrigerator.
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The answer would be <u>a cat running at 5 meters per minute</u>.
Hope this helps :)
