The answer is x=3 because abt+tbc=abc
No it’s not as its not constant and its a fraction
Sqrt 73 = 8.54 (thats rounded to nearest hundredth)
Example...
4^x = 16
log(4^x) = log(16)
x*log(4) = log(16)
x = log(16) / log(4)
<h3><u>Given </u><u>:</u><u>-</u></h3>
- We have given the coordinates of the triangle PQR that is P(-4,6) , Q(6,1) and R(2,9)
<h3><u>To</u><u> </u><u>Find </u><u>:</u><u>-</u></h3>
- <u>We </u><u>have </u><u>to </u><u>calculate </u><u>the </u><u>length </u><u>of </u><u>the </u><u>sides </u><u>of </u><u>given </u><u>triangle </u><u>and </u><u>also </u><u>we </u><u>have </u><u>to </u><u>determine </u><u>whether </u><u>it </u><u>is </u><u>right </u><u>angled </u><u>triangle </u><u>or </u><u>not </u>
<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>
<u>Here</u><u>, </u><u> </u><u>we </u><u>have </u>
- Coordinates of P =( x1 = -4 , y1 = 6)
- Coordinates of Q = ( x2 = 6 , y2 = 1 )
- Coordinates of R = ( x3 = 2 , y3 = 9 )
<u>By </u><u>using </u><u>distance </u><u>formula </u>
<u>Subsitute </u><u>the </u><u>required </u><u>values </u><u>in </u><u>the </u><u>above </u><u>formula </u><u>:</u><u>-</u>
Length of side PQ
Length of QR
Length of RP
<h3><u>Now</u><u>, </u></h3>
We have to determine whether the triangle PQR is right angled triangle
<h3>Therefore, </h3>
<u>By </u><u>using </u><u>Pythagoras </u><u>theorem </u><u>:</u><u>-</u>
- Pythagoras theorem states that the sum of squares of two sides that is sum of squares of 2 smaller sides of triangle is equal to the square of hypotenuse that is square of longest side of triangle
<u>That </u><u>is</u><u>, </u>
<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>,</u>
<u>From </u><u>above </u><u>we </u><u>can </u><u>conclude </u><u>that</u><u>, </u>
- The triangle PQR is not a right angled triangle because 205 ≠ 45 .