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2 years ago

Can someone pls help me with this last question ASAP

Mathematics

2 answers:

hichkok12 [17]2 years ago

8 0

Answer:

your answer will be <u>0</u>

Step-by-step explanation:

$y=ax^{2} +bx +29\\$

axis of symmetry

$x=\frac{-b}{2b}$ when b=0

$x\frac{0}{2b}= 0$

hope it helps :)

have a nice weekend!!!

Misha Larkins [42]2 years ago

6 0

Answer:

y - axis ( x = 0 )

Step-by-step explanation:

Given

y = ax² + bx + c ← when b = 0

y = ax² + c

which is symmetrical about the y- axis

with equation x = 0

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Do any numbers multiply into 7 and add up to 8? or is it unfactorable

faltersainse [42]

1
1x7=7
1+7=8
1 is the answer

5 0

2 years ago

Find the supplement of an angle that measures 20 degrees.

OLEGan [10]

Supplementary angles add to be 180 degrees. If one angle is 20. The supplement angle is 160.
180 - 20 = 160
160 is your answer.

8 0

1 year ago

A second particle, Q, also moves along the x-axis so that its velocity for 0 £ £t 4 is given by Q t cos 0.063 ( ) t 2 v t( ) = 4

Vladimir79 [104]

Answer:

The time interval when $V_Q(t) \geq 60$ is at $1.866 \leq t \leq 3.519$

The distance is 106.109 m

Step-by-step explanation:

The velocity of the second particle Q moving along the x-axis is :

$V_{Q}(t)=45\sqrt{t} cos(0.063 \ t^2)$

So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.

We are also to that :

$V_Q(t) \geq 60$ between $0 \leq t \leq 4$

The schematic free body graphical representation of the above illustration was attached in the file below and the point when $V_Q(t) \geq 60$ is at 4 is obtained in the parabolic curve.

So, $V_Q(t) \geq 60$ is at $1.866 \leq t \leq 3.519$

Taking the integral of the time interval in order to determine the distance; we have:

distance = $\int\limits^{3.519}_{1.866} {V_Q(t)} \, dt$

= $\int\limits^{3.519}_{1.866} {45\sqrt{t} cos(0.063 \ t^2)} \, dt$

= By using the Scientific calculator notation;

distance = 106.109 m

4 0

2 years ago

The total stopping distance T for a vehicle is T = 2.5x + 0.5x 2 , where T is in feet and x is the speed in miles per hour. Appr

Kobotan [32]

Answer:

% change in stopping distance = 7.34 %

Step-by-step explanation:

The stooping distance is given by

$T = 2.5 x + 0.5 x^{2}$

We will approximate this distance using the relation

$f (x + dx) = f (x)+ f' (x)dx$

dx = 26 - 25 = 1

T' = 2.5 + x

Therefore

$f(x)+f'(x)dx = 2.5x+ 0.5x^{2} + 2.5 +x$

This is the stopping distance at x = 25

Put x = 25 in above equation

2.5 × (25) + 0.5× $25^{2}$ + 2.5 + 25 = 402.5 ft

Stopping distance at x = 25

T(25) = 2.5 × (25) + 0.5 × $25^{2}$

T(25) = 375 ft

Therefore approximate change in stopping distance = 402.5 - 375 = 27.5 ft

% change in stopping distance = $\frac{27.5}{375}$ × 100

% change in stopping distance = 7.34 %

6 0

2 years ago

Daniel wants to buy cookies for her friends. The area of a cookie is 113.04 in2. What is the circumference of the cookie?

prisoha [69]

Answer:

The circumference of the cookie is 37.68 inches.

Step-by-step explanation:

We have,

The area of a cookie is 113.04 square inches.

It is circular in shape. The area of circle is given by :

$A=\pi r^2$

r is radius of circle

$r=\sqrt{\dfrac{A}{\pi}} \\\\r=\sqrt{\dfrac{113.04}{3.14}} \\\\r=6\ \text{inch}$

The circumference of circular shaped object is given by :

$C=2\pi r\\\\C=2\times 3.14\times 6\\\\C=37.68\ \text{inch}$

So, the circumference of the cookie is 37.68 inches.

7 0

2 years ago