I think the correct answer from the choices listed above is the first option. The statement that is true for every rotation would be that the image and pre-image are congruent. A<span>ll the rest deals with changing the rotated shape not a constant. Hope this helps.</span>
900,000 because that is where the value of 9 is placed in the number.
Arcsin x + arcsin 2x = π/3
arcsin 2x = π/3 - arcsin x
sin[arcsin 2x] = sin[π/3 - arcsin x] (remember the left side is like sin(a-b)
2x = sinπ/3 cos(arcsin x)-cosπ/3 sin(arc sinx)
2x = √3/2 . cos(arcsin x) - (1/2)x)
but cos(arcsin x) = √(1-x²)===>2x = √3/2 .√(1-x²) - (1/2)x)
Reduce to same denominator:
(4x) = √3 .√(1-x²) - (x)===>5x = √3 .√(1-x²)
Square both sides==> 25x²=3(1-x²)
28 x² = 3 & x² = 3/28 & x =√(3/28)
From the preimage, the angle or point I choose is P and I
name its image as: P maps to P’.
The set of all elements of the domain that map to the members
of S is the inverse image or preimage of a
particular subset S of the codomain of a function.
A = {0, 1, 2, 3}
C = {0, a, 2, b}
A ∩ C = {0, 2} → E)
A set of the same elements from the set A and the set C.