Answer:
Hopes it helps
Step-by-step explanation:
The Quadratic Polynomial is
2 x² +x -4=0
Using the Determinant method to find the roots of this equation
For, the Quadratic equation , ax²+ b x+c=0
(b) x²+x=0
x × (x+1)=0
x=0 ∧ x+1=0
x=0 ∧ x= -1
You can look the problem in other way
the two Quadratic polynomials are
2 x²+x-4=0, ∧ x²+x=0
x²= -x
So, 2 x²+x-4=0,
→ -2 x+x-4=0
→ -x -4=0
→x= -4
∨
x² +x² +x-4=0
x²+0-4=0→→x²+x=0
→x²=4
x=√4
x=2 ∧ x=-2
As, you will put these values into the equation, you will find that these values does not satisfy both the equations.
So, there is no solution.
You can solve these two equation graphically also.
A=16.35
B=21.5. ................
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Hello! remember you have to write complete questions in order to get good and exact answers. Here I'll explain this in a general way assuming the following table:
As you can see, x increases in steps of 1 units. So let's check the difference in y:
So we have a constant difference and we can conclude the table represents a line. Since the line passes through then y is directly proportional to x, so we can write:
Then:
Finally, the equation of the line is:
Opposite sides are parallel
Opposite angles are congruent
Opposite sides are congruent.
The area of the tennis court is computed by multiplying the dimensions given,
A = 120' x 80'
A = 9600 ift
Then, we convert the area in ft² to acres,
A = (9600 in²)(2.3 x 10^-5/ 1 in²)
A = 0.24 acre
The portion of land remaining is,
A of remaining = 0.25 acre - 0.24 acre
= 0.1 acre
The remaining portion is for Andre's studies.
This, 0.1 ft² is equal to the 4% of the given area of the court.
