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Answer:
88.88% probability that it endures for less than a year and a half
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
The next career begins on Monday; what is the likelihood that it endures for less than a year and a half?
One year has 52.14 weeks. So a year and a half has 1.5*52.14 = 78.21 weeks.
So this probability is the pvalue of Z when X = 78.21.
has a pvalue of 0.8888
88.88% probability that it endures for less than a year and a half
Answer:
It takes around 5s for each plane to travel their respective distances.
Step-by-step explanation:
10 × $150 = $1500
88 × $85.50 = $7524
1500 + 7524 = $9024 a day.
9024 × 6 = $54,144 (the answer)
Hope this helps!
Answer:
Step-by-step explanation:
"Find the values of x that satisfy 3x - 2x^2 = 7." Please do not use " × " to represent a variable; " × " is an operator, the "multiply" operator.
Rearrange these three terms in descending order by powers of x:
-2x^2 + 3x - 7 = 0. Here the coefficients are a = -2, b = 3 and c = -7, and so the discriminant of this quadratic is b^2-4ac, or 9 - 4(-2)(-7), or 9 - 56, or -47.
Because the discriminant is negative, we'll have two different complex roots here. The quadratic formula becomes
-3 ± i√47 -3 ± i√47
x = ----------------- = -------------------
2(-2) -4