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1 year ago

HELP PLSSS 20 POINTS!!! ASAP

Mathematics

2 answers:

sukhopar [10]1 year ago

7 0

Answer:

Step-by-step explanation:

did this before so easy

miv72 [106K]1 year ago

6 0

Answer:

Step-by-step explanation:

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Factor z^2 – 3z – 18. A. (z + 3)(z – 6) B. (z – 3)(z – 6) C. (z + 8)(z – 10) D. (z + 2)(z – 9)

ozzi

Work shown above! Answer would be A!

5 0

2 years ago

For the following telescoping series, find a formula for the nth term of the sequence of partial sums

gtnhenbr [62]

I'm guessing the sum is supposed to be

$\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}$

Split the summand into partial fractions:

$\dfrac1{(5k-1)(5k+4)}=\dfrac a{5k-1}+\dfrac b{5k+4}$

$1=a(5k+4)+b(5k-1)$

If $k=-\frac45$ , then

$1=b(-4-1)\implies b=-\frac15$

If $k=\frac15$ , then

$1=a(1+4)\implies a=\frac15$

This means

$\dfrac{10}{(5k-1)(5k+4)}=\dfrac2{5k-1}-\dfrac2{5k+4}$

Consider the $n$ th partial sum of the series:

$S_n=2\left(\dfrac14-\dfrac19\right)+2\left(\dfrac19-\dfrac1{14}\right)+2\left(\dfrac1{14}-\dfrac1{19}\right)+\cdots+2\left(\dfrac1{5n-1}-\dfrac1{5n+4}\right)$

The sum telescopes so that

$S_n=\dfrac2{14}-\dfrac2{5n+4}$

and as $n\to\infty$ , the second term vanishes and leaves us with

$\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}=\lim_{n\to\infty}S_n=\frac17$

7 0

2 years ago

2 A change in the genes of a species over a<br> long period of time.

Blizzard [7]

Answer:

There is no question..?

3 0

2 years ago

Read 2 more answers

HELP ME!!!!!!

denis-greek [22]

Answer:

data set C.

Step-by-step explanation:

This set has a bigger/wider range (1-5)

5 0

2 years ago

Please help i'll mark brainliest if your answer is correct

amid [387]

Split the shape in 3 rectangles
4x2=8x2= 16 ( the bottom and top rectangle)
6x2= 12 (middle rectangle)
16+12=28

6 0

2 years ago