5 km northeast. Left and up would make northeast
Answer:
Given that
speed u=4*10^6 m/s
electric field E=4*10^3 N/c
distance b/w the plates d=2 cm
basing on the concept of the electrostatices
now we find the acceleration b/w the plates to find the horizontal distance traveled by the electron when it hits the plate.
acceleration a=qE/m== m/s
now we find the horizontal distance traveled by electrons hit the plates
horizontal distance
=
== 3 cm
Answer:
It would take time for the capacitor to discharge from to .
It would take time for the capacitor to discharge from to .
Note that , and that.
Explanation:
In an RC circuit, a capacitor is connected directly to a resistor. Let the time constant of this circuit is , and the initial charge of the capacitor be . Then at time , the charge stored in the capacitor would be:
.
<h3>a)</h3>
.
Apply the equation :
.
The goal is to solve for in terms of . Rearrange the equation:
.
Take the natural logarithm of both sides:
.
.
.
<h3>b)</h3>
.
Apply the equation :
.
The goal is to solve for in terms of . Rearrange the equation:
.
Take the natural logarithm of both sides:
.
.
.
<u>We are Given:</u>
Mass of the block (m) = 500 grams or 0.5 Kg
Initial velocity of the block (u) = 0 m/s
Distance travelled by the block (s) = 8 m
Time taken to cover 8 m (t)= 2 seconds
Acceleration of the block (a) = a m/s²
<u>Solving for the acceleration:</u>
From the seconds equation of motion:
s = ut + 1/2* (at²)
<em>replacing the variables</em>
8 = (0)(2) + 1/2(a)(2)²
8 = 2a
a = 4 m/s²
Therefore, the acceleration of the block is 4 m/s²