Answer:
The answer to your question is it is not at equilibrium, it will move to the products.
Explanation:
Data
Keq = 2400
Volume = 1 L
moles of NO = 0.024
moles of N₂ = 2
moles of O₂ = 2.6
Process
1.- Determine the concentration of reactants and products
[NO] = 0.024 / 1 = 0.024
[N₂] = 2/1 = 2
[O₂] = 2.6/ 1= 2.6
2.- Balanced chemical reaction
N₂ + O₂ ⇒ 2NO
3.- Write the equation for the equilibrium of this reaction
Keq = [NO]²/[N₂][O₂]
- Substitution
Keq = [0.024]² / [2][2.6]
-Simplification
Keq = 0.000576 / 5.2
-Result
Keq = 1.11 x 10⁻⁴
Conclusion
It is not at equilibrium, it will move to the products because the experimental Keq was lower than the Keq theoretical-
1.11 x 10⁻⁴ < 2400
Viscosity is the thickness of a liquid, cause by the friction between the molecules in that liquid. A very high viscosity would result in a solid form and low would be a liquid. If a liquid as zero viscosity is only found in superfluids at there freezing points or lower. There are also two types of viscosity “dynamic” (which is measure in seconds, pascal seconds to be exact) and “kinematic” (which is measured in metre per second squared)
Fun fact they use viscosity to predict when volcanoes are going to erupt:)
Hope this helps I love sciencey stuff so if you need anymore help let me know!
Elements always exist as pair of atoms called molecules .
Explanation:-
- The material which has only one types of similar atoms called element .
- Ex:-Sodium,Carbon etc
It depends on the type of decay that's taking place, but if it's b+ it'd decay into Mn-52. If it's b- it'd decay into Co-59 (i'm sure??)
Answer:
233 g
Explanation:
Let's consider the following reaction.
CaCO₃ → CaO + CO₂
We can establish the following relations:
- The molar mass of calcium carbonate is 100.09 g/mol.
- The molar ratio of calcium carbonate to carbon dioxide is 1:1.
- The molar mass of carbon dioxide is 44.01 g/mol
The mass of carbon dioxide produced from 530 g of calcium carbonate is: