Answer:
141g of CCl₄
Explanation:
First, we have to write the balanced equation.
CCl₄(g) + 2 HF(g) ⇄ CF₂Cl₂(g) + 2 HCl(g)
We can calculate how many moles of CF₂Cl₂ using the ideal gas equation.
V = 14.9 dm³ = 14.9 L
T = 21°C + 273.15 = 294.15 K
P = 1.48 atm
R = 0.08206 atm.L/mol.K
We can use proportions to find the mass of CCl₄ required to obtain 0.914 moles of CF₂Cl₂. According to the balanced equation, 1 mol of CF₂Cl₂ is produced when 1 mol of CCl₄ reacts. And the molar mass of CCl₄ is 154 g/mol.
Would that be mass times volume?
KClO3 (aq) will have greater molar entropy than KClO3 (s) because molar entropy increases with increase in temperature.
As the temperature rises, the standard molar entropy of any substance rises. Entropy and a Single Substance's Temperature ” Entropy increases significantly when a solid turns into a liquid and when a liquid turns into a gas. The entropy of the liquid is lower than that of the gas. As a result, entropy rises in reactions that produce gaseous byproducts from solid or liquid reactants. When solid reactants produce liquid products, entropy also rises.
Learn more about Molar entropy here-
brainly.com/question/3627396
#SPJ4
Answer:
C.
Explanation:
You have to just know this. Their is really no other explanation.
- Hope that helps! Please let me know if you need further explanation.
What equations ? I would like to help
