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2 years ago

Helps me solve this problem please

Mathematics

2 answers:

Vika [28.1K]2 years ago

8 0

Answer:

(1,1) and (-2,-11) are the correct solutions

EleoNora [17]2 years ago

8 0

Answer:

D. (1, 1) and (-2, -11)

Step-by-step explanation:

A's answers:

Coordinates: (0, -3) and (-1, -1)

Equations when they get solved:

4(0)-3=-3 (correct)

4(-1)-3=-1 (incorrect)

B's answers:

Coordinates: (-2, -5) and (2, 5)

Equations when they get solved:

4(-2)-3=-11 (incorrect)

4(2)-3=5 (correct)

C's answers:

Coordinates: (0, 3) and (3, 9)

Equations when they get solved:

4(0)-3=-3 (incorrect)

4(3)-3=9 (correct)

D's answers:

Coordinates: (1, 1) and (-2, -11)

Equations when they get solved:

4(1)-3=1 (correct)

4(-2)-3=-11 (correct)

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Anika [276]

Answer:

A is at 1 1/8

B is at 2 3/8

C is at 3 4/8 or 3 1/2

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Step-by-step explanation:

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2 years ago

A random sampling of a company's monthly operating expenses for n=36 months produced a sample mean of $5474 and a stan-dard devi

lilavasa [31]

Answer with explanation:

Mean of the sample(m) = $ 5474

Standard deviation of the sample (S)=764

Number of observation(n)=36

$Z_{90 \text{Percent}}=Z_{0.09}=0.5359$

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So, Mean Monthly Expenses of Population =$ 5405.76, which is 90% upper confidence bound for the company's mean monthly expenses.

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2 years ago

Complete this question _percent is of 50 shirts is 35 shirts NEED HELP ASAP PLEASE HELP !!!!!!!!!!

svetoff [14.1K]

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2 years ago

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Need help please...answer correctly

Lelechka [254]

Answer:

9.09

Step-by-step explanation:

x=speed of boat

y=speed of water current

Downstream relative speed = x+y

Upstream relative speed = x-y

Distance remains the same for both upstream and downstream.

a) Distance travelled downstream = speed x time = 3(x+y)

Distance travelled upstream = speed x time = 3.6(x-y)

b) Since both distances are equal, we can write

3(x+y)= 3.6(x-y)

3x+3y = 3.6x-3.6y

6.6y = 0,6x

x=11y: y=x/11

c) Water current has speed as 1/11 times of that of boat

In percent this equals 100/11 = 9.09%

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2 years ago

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