Answer: 90% confidence interval is; ( - 0.0516, 0.3752 )
Step-by-step explanation:
Given the data in the question;
n1 = 72, n2 = 17
P1 = 54 / 72 = 0.75
P2 = 10 / 17 = 0.5882
so
P_good = 0.75
P_bad = 0.5882
standard ERRROR will be;
SE = √[(0.75×(1-0.75)/72) + (0.5882×(1-0.5882)/17)]
SE = √( 0.002604 + 0.01424)
SE = 0.12978
given confidence interval = 90%
significance level a = (1 - 90/100) = 0.1, |Z( 0.1/2=0.05)| = 1.645 { from standard normal table}
so
93% CI is;
(0.75 - 0.5882) - 1.645×0.12978 <P_good - P_bad< (0.75 - 0.5882) + 1.645×0.12978
⇒0.1618 - 0.2134 <P_good - P_bad< 0.1618 + 0.2134
⇒ - 0.0516 <P_good - P_bad< 0.3752
Therefore 90% confidence interval is; ( - 0.0516, 0.3752 )
Answer:
Hello! I hope I am correct! :)
Step-by-step explanation:
Let’s first calculate the black circle & the white space.
Since there is more white space than the black circle, we already know that the white space will have more probability.
These are the steps you need to do, in order to so love this problem:
1. Find the area of both, the white space and the black circle.
2. Divide both of them by the area of the square.
3. Do all these steps to find the probability/hitting.
Part A:
Black circle: ( π *1^2) / ( π 5^2) = 1/25 = .04 or 3.14% chance.
So we can tell it’s close to zero.
Part B: 1 - .04 = 0.96 or 97%
This is close to one.
(Remember I am not saying the exact, it’s a estimate)
Brainliest would be appreciated!
Hope this helps! :)
By; BrainlyAnime
From what I am looking at, it seems as if it is. :)
