(2/3)-j
put it in parenthesis, the 2/3 to solve it correctly.
(x+6)^(1/2)-5=x+1
(x+6)^(1/2)=x+6
((x+6)^(1/2))^2=(x+6)^2
x+6=x^2+12x+36
0=x^2+11x+30
(-11+(11^2-4(1)(30))^(1/2))/2
(-11+((1)^(1/2))/2
(-11+1)/2=-5
(-11-1)/2=-6
((-6)+6)^1/2-5=(-6)+1
(0^(1/2))-5=-5
-6 is non-extraneous
((-5)+6)^1/2-5=(-5)+1
(1^1/2)-5=-4
1-5=-4
-4=-4
-5 is non-extraneous
We want to get rid of the stuff in the denomenator
gcd of the denomenator is 2x
but wait, we can get rid of the deonmenator in the numerator by multiplying by 4x
muliplty the whole thing by 4x/4x
we get
option 3
they are corresponding angles and are congruent