(-1,5) to (4,1). Round to nearest tenth

Mathematics

1 answer:

Sunny_sXe [5.5K]2 years ago

4 0

Answer:

6.40

Hope this helped somehow

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Multiply. (7x-4)(4x-3)

dlinn [17]

Your answer is 28x^2-37x+12

1) Use the FOIL method: (a+b)(c+d)=ac+ad+bc+bd

28x^2-21x-16x+12

2) Collect like terms

28x^2+(-21-16x)+12

3) Simplify

28x^2-37x+12

7 0

2 years ago

Read 2 more answers

Can u find the area of these please

Schach [20]

Area of a rectangle can be calculated by multiplying the length by the height.
So:

l x w
3 x 13
39 cm squared

Area of a triangle can be calculated by multiply the length by the height and dividing by two. So:

1/2 x l x w
1/2 x 10 x 8
40 m squared

4 0

3 years ago

Prove the theorem (AB )^T= B^T. A^T

Lisa [10]

Answer:

$(AB)^T = B^T.A^T (Proved)$

Step-by-step explanation:

Given (AB )^T= B^T. A^T;

To prove this expression, we need to apply multiplication law, power law and division law of indices respectively, as shown below.

$(AB)^T = B^T.A^T\\\\Start, from \ Right \ hand \ side\\\\B^T.A^T = \frac{B^T.A^T}{A^T}.\frac{B^T.A^T}{B^T} (multiply \ through) \\\\ = \frac{A^{2T}.B^{2T}}{A^T.B^T} \\\\=\frac{(AB)^{2T}}{(AB)^T} \ \ (factor \ out \ the power)\\\\= (AB)^{2T-T} \ (apply \ division \ law \ of \ indices; \ \frac{x^a}{x^b} = x^{a-b})\\\\= (AB)^T \ (Proved)$