Given Information:
Total cards = 108
Red cards = 25
yellow cards = 25
Blue cards = 25
Green cards = 25
Wild cards = 8
Required Information:
Probability that a hand will contain exactly two wild cards in a seven-hand game = ?
Answer:
P = (₈C₂*₁₀₀C₅)/₁₀₈C₇
Step-by-step explanation:
The required probability is given by
P = number of ways of interest/total number of ways
The total number of ways of dealing a seven-card hand is
₁₀₈C₇
We want to select exactly 2 wild cards and the total wild cards are 8 so the number of ways of this selection is
₈C₂
Since the game is seven-card hand, we have to get the number of ways to select remaining 5 cards out of (108 - 8 = 100) cards.
₁₀₀C₅
Therefore, the setup for this problem becomes
P = number of ways of interest/total number of ways
P = (₈C₂*₁₀₀C₅)/₁₀₈C₇
This is the required setup that we can type into our calculators to get the probability of exactly two wild cards in a seven-hand card game with 8 wild cards and 108 total cards.
A. £549 376 / 4 = £137344 per word
B. £549 376 / 16 = £34336 per letter
C. £549 376 / 37 = £14848 per letter
D. £549 376 / 512 = £ 1073
Answer:
4
Step-by-step explanation:
Divide 5 on both sides, to get x=4
Answer:
Size of N(S) = 90, or S=90
Step-by-step explanation:
So since there are 10 items:
Each single item has 9 possibilities to be paired with, since it is drawn without replacement, and 1 item can't be drawn again.
So : 10 items x 9 possibilites = array of 90
SO ANSWER : 90
Hope I helped :)
Answer:
The larger angle is 54°
Step-by-step explanation:
Given
Let the angles be: θ and α where
θ > α
Sum = 72
α : θ = 1 : 3
Required
Determine the larger angle
First, we get the proportion of the larger angle (from the ratio)
The sum of the ratio is 1 + 3 = 4
So, the proportion of the larger angle is ¾.
Its value is then calculated as:.
θ = Proportion * Sum
θ = ¾ * 72°
θ = 3 * 18°
θ = 54°