In ΔEFG, the measure of ∠G=90°, the measure of ∠E=6°, and GE = 71 feet. Find the length of EF to the nearest tenth of a foot.

Mathematics

2 answers:

o-na [289]2 years ago

4 0

Answer:

71.4

Step-by-step explanation:

cos 6 = 71 / x = 71.4

djyliett [7]2 years ago

3 0

Answer:68.2

Step-by-step explanation:

cos6=71/EF

cos6= 0.960170286650366

0.960170286650366= 71/EF

0.960170286650366*71=EF

EF= 68.2

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