Is c quadratic trinomial I have the same quiz
Answer:
11
Step-by-step explanation:
The angles will equal 180.
Thus, the equation is 9x-5+6x+20=180.
15x+15=180.
15x=165.
divide by 15 on both sides, x = 11.
Answer:
Tap A 3hrs
Tap B 6hrs
Step-by-step explanation:
Let the volume of the swimming pool be Xm^3.
Now, to get the appropriate volume, we know we need to multiply the rate by the time. Let the rate of the taps be R1 and R2 respectively, while the time taken to fill the swimming pool be Ta and Tb respectively.
x/Ta= Ra
x/Tb= Rb
X/(Ra + Rb)= 2
Ta = Tb - 3
From equation 2:
X = 2( Ra + Rb)
Substituting the values of Ra and Rb Using the first set of equations
X = 2( x/Ta + x/Tb)
But Ta = Tb - 3
1/2 = 1/(Tb - 3)+ 1/Tb
0.5 = (Tb + Tb-3)/Tb(Tb - 3)
At this juncture let’s say Tb = y
0.5 = (2y - 3)/y(y - 3)
y(y-3 ) = 4y - 6
y^2 -3y - 4y + 6 = 0
y^2 -7y + 6= 0
Solving the quadratic equation, we get y =
y = Tb = 6hrs or 1hr
We remove one hour as we know that Tap A takes 3hrs left than tap B and there is nothing like negative hours
Now, we get Ta by Tb -3 = 6 - 3 = 3hrs
This is the only way I can think of this mathematically. This took a good 20 minutes for me. You need to guess and check. Like try 17 quarters, 50 nickels, and 37 dimes etc. until you get 11.00. My numbers are mathematically correct but we both know you cant have 18.909 quarters so. lol
Answer:
Quarters: 18.909
Nickels: 49.818
Dimes: 37.818
Somewhere around those numbers.
Step-by-step explanation:
$11.00 total in coins
Nickel = $0.05
Dime = $0.10
Quarter = $0.25
(n*0.05) + (d*0.10) + (q*0.25)
Solve the equation for q.
(n*0.05) + (d*0.10) +( *0.25)
Simplify the expression.
9d + 2n = 440
d - n = -12
Multiply both sides of the equation by -9.
-9d + 9n = 108
9d + 2n = 440
Sum the equations vertically to eliminate at least one variable.
11n = 548
Substitute the given value of n into the equation d - n = -12
Substitute the given value of n into the equation
Finally
d = 37.818
n = 49.818
q = 18.909
Answer:
2nd debate was 3 hours long.
Step-by-step explanation:
We have been given that during the mayoral election,two debates were held between the candidates. The first debate lasted 1 2/3 hours. The second one was 1 4/5 times as long as the first one.
Let us find the estimate of time spent on 2nd debate.
1 2/3 hours would be approximately 2 hours. 1 4/5 times would be equal to 2 times.
Therefore, the estimated time is less 4 hours.
To find the time spent on 2nd debate, we will multiply 1 2/3 by 1 4/5.
First of all, we will convert mixed fractions into improper fractions as:
Now, we will multiply both fractions as:
Therefore, the 2nd debate was 3 hours long.