-0.65
-3/8
2/4
5/16
I hope this is right, the negatives should go first because you are taking away, then positives
3 : 3,6,9,12,15,18,21,24,27,30
4 : 4,8,12,16,20,24,28,32,36
7: 7,14,21,28,35,42,49,56,63
9: 9,18,27,36,45,54,63,72,81
Answer:
20 in³
Step-by-step explanation:
Area of a triangle is half the base times the perpendicular height:
A=0.5bh
=0.5*10*4
=20
The car's average rate is 43.7 mph. The bicycle's average rate is 12.3 mph.
To get this solution, let the bicycle's average rate be (x) and the car's average rate be (x + 31.4) mph.
Distance= Speed x Time
364 = (x + x + 31.4) 6.5
364 = (2x + 31.4) 6.5
364/6.5 = 2x + 31.4
56 = 2x + 31.4
56 - 31.4 = 2x
24.6 = 2x
24.6/2 = x
12.3 = x
x = 12.3 mph
x+31.4 = 43.7 mph
Answer:
Step-by-step explanation:
5x+20 = 0
5X= -20
X= -20/5 = -4
8(4n+3) = 32n+24 =0
32n = -24
n = -24/32 = -3/4
12n-6=0
12n =6
n = 6/12 = 1/2
9(2x+9)
18x+81 =0
18x= -81
x= -81/18 = -9/2= -4.5
36+9y=0
36=-9y
36/-9 = y = -4
7(n-3) = 0
7n-21=0
7n = 21
n = 21/7
n=3
21+15a = 0
21= -15a
a= 21/-15 = 7/-5 = -1.4
32x-12x=0
20x=0
x=0/20 = 0
n-4-9=0
n-13=0
n=13
-3x-9+15x=0
-3x+15x-9 =0
12x-9=0
12x=9
x=9/12 = 3/4 = 0.75
-16N-14N=0
-30n=0
n=0/-30 =0
-10-90x-6x-10x²-2
-10-2-96x-10x²
-12-96x-10x²
10x²+96x+12
x= -b±√b²-4(a)(c)/2a
{-96±√96²-4(10)(12)}/2(10)
{-96±√(9216-480)}/20
-96±√8736/20
-96±(93.4665715644)/20
-96+93.4665715644/20 -96-93.4665715644/20
-2.5334284356/20 -189.466571564/20
-0.12667142178≅ -0.13 -9.4733285782≅ -9.47
-0.13 -9.47
-5(9n+9) =0
-45n-45 =0
-45n = 45
n = 45/-45 =-1
-5n+3(6+7n)
-5n+18+21n=0
-5n+21n+18 =0
16n+18 =0
16n = -18
n = -18/16 = -9/8 = -1.125
-4+7(1-3n)=0
-4+7-21n=0
3-21n=0
3=21n
3/21=n = 1/7
3n-(2n-8)
3n-2n+8=0
n+8=0
n=-8
