Answer:
2 miles
Step-by-step explanation:
1 in=4miles
0.5 in=2miles
so divide by two on each side
First you distribute...
-2n - 6 - 35 - 14n
Then you simplify...
-16n - 41
Done
Answer:
Five and Six hundred Forty one thousandths
Step-by-step explanation:
5.641 in words can be written as
the first number is considered same, decimal is considered as and and digits after decimal are considered as regular number.
So, 5.641 in word form is:
Five and Six hundred Forty one thousandths
Surface area of a cone = π{rs+r²}<br /> =πr{s+r}<br />part 1:if π is 6 units and s is 4 units then r would be 3.14 ×6 {4+6}<br /><br />part 2: area of a cone = 3.14 ×6×10<br /> =31.4×6<br /> = 188.4 units²<br />the surface area = 188.4 <br />units²<br /> hope i helped
Answer:
(E) 0.71
Step-by-step explanation:
Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.
So, the probability that the student has a GPA lower than 3.5 and is not taking any AP classes is calculated as:
P(A'∩B') = 1 - P(A∪B)
it means that the students that have a GPA lower than 3.5 and are not taking any AP classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.
Therefore, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled in at least one AP class is 0.12
So, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∪B) = 0.25 + 0.16 - 0.12
P(A∪B) = 0.29
Finally, P(A'∩B') is equal to:
P(A'∩B') = 1 - P(A∪B)
P(A'∩B') = 1 - 0.29
P(A'∩B') = 0.71
