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AleksAgata [21]

2 years ago

12

Oliver has a piece of chocolate what is the volume of the piece of chocolate

1 answer:

OLga [1]2 years ago

4 0

Answer:

The answer would be 60 cubic centimeters.

Step-by-step explanation:

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Convert from general form to standard form x^2 + 4y^2 + 6x-40y+9 =0

Burka [1]

$x^2 + 4y^2 + 6x-40y+9 =0\\x^2 + 6x+9+4y^2-40y=0\\x^2+6x+9+4y^2-40y+100-100=0\\(x+3)^2+(2y-10)^2=100$

P.S. Hello from Russia

7 0

2 years ago

PLEASEEEE help <br> i know i am saying this again

BartSMP [9]

Answer: for the first it is not direct varition while for the second one it i s

Step-by-step explanation:

6 0

6 months ago

HELP PLEASE!!! 10 PTS!!

allsm [11]

Answer:

m∠DEC = 78°

Step-by-step explanation:

Given information: AC = AD, AB⊥BD, m∠DAC = 44° and CE bisects ∠ACD.

If two sides of a triangles are congruent then the opposite angles of congruent sides are congruent.

AC = AD (Given)

$\angle ADC\cong \angle ACD$

$m\angle ADC=m\angle ACD$

According to the angle sum property, the sum of interior angles of a triangle is 180°.

$m\angle ADC+m\angle ACD+m\angle DAC=180$

$m\angle ACD+m\angle ACD+44=180$

$2m\angle ACD=180-44$

$2m\angle ACD=136$

Divide both sides by 2.

$m\angle ACD=68$

CE bisects ∠ACD.

$m\angle ACE=m\angle DCE=\dfrac{\angle ACD}{2}$

$m\angle ACE=m\angle DCE=\dfrac{68}{2}$

$m\angle ACE=m\angle DCE=34$

Use angle sum property in triangle CDE,

$m\angle CDE+m\angle DCE+m\angle DEC=180$

$68+34+m\angle DEC=180$

$68+34+m\angle DEC=180$

$102+m\angle DEC=180$

Subtract 102 from both sides.

$m\angle DEC=180-102$

$m\angle DEC=78$

Therefore, the measure of angle DEC is 78°.

6 0

2 years ago

Select the correct answer.

vovangra [49]

Answer:

B

Step-by-step explanation:

think of the ratios as equivalent fractions. 2 over 14 is NOT equal to 3 over 42.

6 0

2 years ago

25% $760 what's the answer

Semenov [28]

The answer would be $190

5 0

2 years ago