Strictly speaking, x^2 + 2x + 4 doesn't have solutions; if you want solutions, you must equate <span>x^2 + 2x + 4 to zero:
</span>x^2 + 2x + 4= 0. "Completing the square" seems to be the easiest way to go here:
rewrite x^2 + 2x + 4 as x^2 + 2x + 1^2 - 1^2 = -4, or
(x+1)^2 = -3
or x+1 =i*(plus or minus sqrt(3))
or x = -1 plus or minus i*sqrt(3)
This problem, like any other quadratic equation, has two roots. Note that the fourth possible answer constitutes one part of the two part solution found above.
Answer:
1178.25cm^3
Step-by-step explanation:
Volume of a cylinder is given as V = Pi x r^2 xh
PI= 3.142
R = 5cm
H=15cm
So volume = 3.142 x 5cm x 5cm x 15cm
= 1178.25cm^3
Answer:
x ≥ -5
Step-by-step explanation:
If we have a translation to left c units, we write " x + c " in the function, and
If we have a translation to right c units, we write " x - c" in the function
If we have vertical translation up b units, we "add b to the function", and
If we have vertical translation down b units, we "subtract b to the function"
The parent function is
Since translation left 5 units and up 3 units, we can write:
The domain is affected by the square root sign and we know the number under the square root CANNOT be negative, so we can say:
x + 5 ≥ 0
x ≥ -5
This is the domain.
Answer:
6
Step-by-step explanation:
2 to the power of 1 is 2, anything to the power of one is the original number itself. 3*2=6
Answer:
Step-by-step explanation:
1.44x2.2=3.168 pounds