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2 years ago

In the triangle below, find the value of a/// Please help!

Mathematics

1 answer:

sergiy2304 [10]2 years ago

3 0

Answer:

a= 45

Step-by-step explanation:

all angles equal 180 degrees so you take the angle given which is 45 and the other which is a right angle, or 90 degrees and subtract 45 from 90 and you get 45 so a = 45 and you add up 45 + 45 + 90 thats 180!

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Write 305,501 in expanded form

WINSTONCH [101]

That would be

300,000 + 5,000 + 500 + 1

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2 years ago

Josie says that (-15) XX(-15) = -156. Is she correct? How do you know?

notka56 [123]

-21 i think is should be

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2 years ago

HIII I need help with this I just took a screenshot its for 7th grade.

Kitty [74]

I believe it’s

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1 year ago

Divya spends all of her free time playing with her building blocks. She owns building block sets with 333 pieces, 555 pieces, an

DiKsa [7]

Answer:

5 sets

Step-by-step explanation:

The average number of pieces per set is the ratio of the total number of pieces to the total number of sets.

Let x represent the number of 3-piece sets. Then the total number of pieces is ...

3x +5(5) +10(2) = 3x +45

The total number of sets is ...

x +5 +2 = x +7

We want the ratio of these numbers to be 5 pieces per set:

(3x +45)/(x +7) = 5

3x +45 = 5x +35 . . . . . multiply by (x+7)

10 = 2x . . . . . . . . . . subtract (3x+35)

5 = x . . . . . . . . . divide by 2

Divya owns 5 sets with 3 pieces.

_____

<em>Alternate solution</em>

Each 10-piece set has 5 more pieces than average, so the two of them total 10 more pieces than average.

Each 3-piece set has 2 fewer pieces than average. The total number of 3-piece sets must have a total of 10 fewer pieces than average in order to balance the excess of the 10-piece sets. That is, there must be 10/2 = 5 of the 3-piece sets to have a total lof 10 fewer pieces than average.

Altogether, the differences from average must total zero.

5 0

2 years ago

Student scores on exams given by a certain instructor have mean 74 and standard deviation 14. This instructor is about to give t

Lapatulllka [165]

Answer:

$P(\bar X >80)=P(Z>2.143)=1-P(z$

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Let X the random variable that represent the Student scores on exams given by a certain instructor, we know that X have the following distribution:

$X \sim N(\mu=74, \sigma=14)$