2 years ago

The length of a photograph is 4 in. greater than its width. The area of the photograph is

1 answer:

Aleks [24]2 years ago

8 0

Answer:

208.........not sure but this can be the ans

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WITCHER [35]

It would be 20 so you had it right

5 0

2 years ago

MAVERICK [17]

the answer is

8y^3y−4 −6y^3y−5

4 0

2 years ago

Marina86 [1]

Answer:

The area of Nancy's garden is $16\frac{7}{8}\ yd^{2}$

Step-by-step explanation:

I assume that the Nancy's garden is a rectangle shape

To find the area first convert mixed number to an improper fraction

$4\frac{1}{2}\ yd=\frac{4*2+1}{2}=\frac{9}{2}\ yd$

$3\frac{3}{4}\ yd=\frac{3*4+3}{4}=\frac{15}{4}\ yd$

Therefore

The area is equal to

$A=\frac{9}{2}*\frac{15}{4}=\frac{135}{8}\ yd^{2}$

convert to mixed number

$\frac{135}{8}\ yd^{2=\frac{128}{8}+\frac{7}{8}=16\frac{7}{8}\ yd^{2}$

4 0

2 years ago

rodikova [14]

U do 5 times 30 and get 150 then take 15 times 50 and get 750 last take 750 plus 150 and u get 900 cm

7 0

2 years ago

zlopas [31]

2 1/2 x 3 = 7 1/2 = 7 4/8

10 11/8
- 7 4/8
3 7/8
A is the correct answer

7 0

2 years ago