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2 years ago

Ms. Houston's fifth-grade class of 20 students is going to a museum.

Mathematics

1 answer:

nydimaria [60]2 years ago

3 0

Answer:

7 fossils

Step-by-step explanation:

Find the cost for transportation by multiplying 20 by 5, since it is $5 per student and there are 20 students

20(5)

= 100

Subtract this from 128, since they raised $128

128 - 100

= 28

This means they have $28 to spend on fossils.

To find how many they can buy, divide 28 by 4, since they are $4 each

28/4

= 7

So, they can buy 7 fossils with the money they have left

You might be interested in

7x-14y=-28<br> 2x+7y=-14

Svetach [21]

Answer:

Step-by-step explanation:

x=0 and y=-2

4 0

2 years ago

Having a small brain moment, can you please help and show work

ankoles [38]

Answer:

The value if x is 0.9875.

Step-by-step explanation:

First, we have to get rid of brackets by expanding :

$0.5(2x + \frac{3}{4} ) - \frac{1}{3} (0.1 + x) = 1$

$0.5(2x) + 0.5( \frac{3}{4} ) - \frac{1}{3} (0.1) - \frac{1}{3} (x) = 1$

$x + \frac{3}{8} - \frac{1}{30} - \frac{1}{3} x = 1$

Next you have to collect like terms :

$x - \frac{1}{3} x + \frac{3}{8} - \frac{1}{30} = 1$

$\frac{2}{3} x + \frac{41}{120} = 1$

Lastly, you can solve x :

$\frac{2}{3} x = 1 - \frac{41}{120}$

$\frac{2}{3} x = \frac{79}{120}$

$x = \frac{79}{120} \div \frac{2}{3}$

$x = \frac{79}{80}$

$x = 0.9875$

8 0

2 years ago

Which of the following sets could be the sides of a right triangle?

coldgirl [10]

Answer: Choice B) {3, 5, sqrt(34)}

=====================================

Explanation:

We can only have a right triangle if and only if a^2+b^2 = c^2 is a true equation. The 'c' is the longest side, aka hypotenuse. The legs 'a' and 'b' can be in any order you want.

-----------

For choice A,

a = 2

b = 3

c = sqrt(10)

So,

a^2+b^2 = 2^2+3^2 = 4+9 = 13

but

c^2 = (sqrt(10))^2 = 10

which is not equal to 13 from above. Cross choice A off the list.

-----------

Checking choice B

a = 3

b = 5

c = sqrt(34)

Square each equation

a^2 = 3^2 = 9

b^2 = 5^2 = 25

c^2 = (sqrt(34))^2 = 34

We can see that

a^2+b^2 = 9+25 = 34

which is exactly equal to c^2 above. This confirms the answer.

-----------

Let's check choice C

a = 5, b = 8, c = 12

a^2 = 25, b^2 = 64, c^2 = 144

So,

a^2+b^2 = c^2

25+64 = 144

89 = 144

which is a false equation allowing us to cross choice C off the list.

7 0

2 years ago

Out of the total respondents, the percentage of respondents from the 46–55 age group who rated the film excellent is %. write yo

Mrrafil [7]

Missing data:

Viewer's Age Group Excellent Good Average Poor Marginal Total

16–25 52 42 12 7 113

26–35 33 50 5 9 97

36–45 58 12 28 34 132

46–55 25 17 22 12 76

56 + 12 5 3 8 28

Marginal Total 180 126 70 70 446

A rating of good or excellent indicates the audience liked the movie, while a rating of poor indicates the audience disliked the movie.

<h3>How to determine the rating of the film from the 46–55 age group?</h3>

A movie producer accomplished a survey behind a preview screening of her latest movie to estimate how the film would be accepted by viewers from various age groups. The table displays the numbers of viewers in various age groups who ranked the film excellent, good, average, and poor.

25/446 = 0.05605

0.05605 $*$ 100% = 5.605%