Answer:
Percentage by mass of calcium carbonate in the sample is 93.58%.
Explanation:
Assumptions:
- calcium carbonate was dissolved completely and the amount of carbon dioxide released was proportional to the amount of calcium carbonate.
- the sample did not contain any other compound that released or reacted with carbon dioxide.
given the equation of the reaction:
from assumption:
amount carbon dioxide = amount of calcium carbonate
reacting mass ( m ) = Molar Mass ( M ) * Amount ( n )
m = 0.04938397 * 100 = 4.93839
percentage by mass of CaC = .
Answer:
The concentration of the CaBr2 solution is 96 µmol/L
Explanation:
<u>Step 1:</u> Data given
Moles of Calciumbromide (CaBr2) = 4.81 µmol
Volume of the flask = 50.0 mL = 0.05 L
<u>Step 2:</u> Calculate the concentration of Calciumbromide
Concentration CaBr2 = moles CaBr2 / volume
Concentration CaBr2 = 4.81 µmol / 0.05 L
Concentration CaBr2 = 96.2 µmol /L = 96.2 µM
The concentration of the CaBr2 solution is 96 µmol/L
Answer:
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The wave length of light. This determinds the color/type of light.
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