17/80 = p/100
p = 17/80 * 100
p = 0.2125 * 100
p = 21.25
The equation which models the distance (d) of the weight from its equilibrium after time (t) is equal to d = -9cos(2π/3)t.
<h3>What is the period of a cosine function?</h3>
The period of a cosine function simply means the total length (distance) of the interval of values on the x-axis over which a graph lies and it's repeated.
Since the weight attached is at its lowest point at time (t = 0), therefore, the amplitude of equation will be negative nine (-9)
For the angular velocity at time period (t = 3s), we have:
ω = 2π/T
ω = 2π/3
Mathematically, the standard equation of a cosine function is given by:
y = Acos(ω)t
Substituting the given parameters into the formula, we have;
d = -9cos(2π/3)t.
Read more on cosine function here: brainly.com/question/4599903
X and x+ 2 equal 188
add all the like terms to get 2x+2=188
subtract 2 from each side
2x=186
divide by 2
x=93
so the numbers are 93 and 95
Answer:
Step-by-step explanation:
6/4=(6-1)/(4-x)
6/4=5/(4-x)
6(4-x)=4(5)
24-6x=20
-6x=-4
x=4/6
x=2/3
2/3 of an inch should be cut off the width.
Answer:
Accelerating to top speed, deaccelerating to finish line.
Step-by-step explanation:
If the runner kept a constant speed of 11 mph for the whole duration of his run (32 minutes), the distance he would have covered is:
This means that, in order to run the full 6.2 miles, the runner needs to reach a speed over 11 mph. Assume he starts from rest, while accelerating the runner reaches, and the surpasses, the 11 mph mark. Since his speed at the finish line is zero, the runner has to deaccelerate from his current running speed (which should be higher than 11 mph), passing through 11 mph and reaching zero at the finish line.