Answer:
Peter Jonathan Winston (March 18, 1958 – disappeared January 26, 1978) was an American chess player from New York City
Step-by-step explanation:
In late 1977, Winston attended a FIDE-rated tournament at Hunter College High School in New York City. Despite being one of the highest-rated players in the tournament, Winston lost all nine of his games. A few months later, on January 26, 1978, following further surprising game losses, Peter Winston vanished and was never heard from again. According to some sources, Winston's disappearance occurred when he left his home without money, identification, or luggage during a severe winter storm. Many chess players who were close to or acquainted with Winston claim that the champion chess player's mental health had deteriorated, along with his game performance, in the last few years of his life, and that the decline in his mental health may have led to his disappearance.
Hey There!
Lets Just Work through your answers,
ⓧ A - An isosceles triangle is a triangle with (at least) two equal sides, so this would not apply to the given triangle.
:) B - A scalene triangle is a triangle in which all three sides have different lengths so this applies to the given triangle. One side measures 10, one measures 11, and one measures 12.1
ⓧ C - A right triangle is a type of triangle that has one angle that measures 90 degrees, which this triangle does not so this does not apply.
ⓧ D - In geometry, an equilateral triangle is a triangle in which all three sides are equal, so this does not apply to the given triangle.
ⓧ E - An obtuse triangle is a triangle with one obtuse angle (greater than 90°) and two acute angles, so this does not apply to the given triangle.
:) F - An acute triangle (or acute-angled triangle) is a triangle with three acute angles less than 90 degrees. So this applies to the given triangle.
In Summary, B & F classify the given triangle correctly.
If you could rate five starts & give brainliest that would be greatly appreciated!
Hope I helped, Have a good day.
Answer:
Approximately 24–36 pounds
Step-by-step explanation:
Given:
Weight of standard American Eskimo dog has mean= 30 pounds
A standard deviation= 2 pounds
For 99.7% of the dogs according to normal distribution would lie between 3 standard deviations on either side of the mean.
i.e. lower bound= Mean- 3 (standard deviation)
= 30-3(2)
=30-6
=24
Upper bound = Mean +3 (standard deviation)
= 30+3(2)
=30+6
=36
Hence the range of weights : 24-36 pounds
correct answer Approximately 24–36 pounds!
Answer:
44
Step-by-step explanation:
Math boi
Answer:
The equations represent circles that result in the same graph.
Step-by-step explanation:
we have
Divide by -10 both sides
-----> equation A
This is the equation of a circle centered at origin with radius 
and
Divide by 5 both sides
-----> equation B
This is the equation of a circle centered at origin with radius
equation A and equation B are equal
therefore
The system has infinite solutions, because the equations represent circles that result in the same graph.
