What is the hybridization state on the central N atom in the azide ion, N3−?
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Answer:
Explanation:
Data Given
Formula of hydrazine = N₂H₄
Lewis structure of hydrazine (N₂H₄) =?
Solution:
- Hydrazine (N₂H₄) contains 2 Nitrogen atoms and 4 Hydrogen atoms
- Nitrogen atom have 5 valence electrons
- Hydrogen have 1 valance electron
- So it have 14 total number of valance electrons
N₂ H₄ = 2 (5) + 4(1) = 14 no. o electrons
- it is a stable compound and obey octet rule for nitrogen and duplet rule for hydrogen by sharing of electrons.
To draw the Lewis Structure
- Put the 2 nitrogen in center and draw the Hydrogen on the outside
- Put the 2 hydrogen on out side of each of the nitrogen
- Then draw the 2, 2 valence electrons between atoms that form chemical bond
- So we will draw total 14 electrons in the structure
- then we count electrons around each atom of nitrogen and hydrogen that it have 8 and 2 electrons to complete its octet and duplet respectively
Lewis Structure of N₂ H₄ in attachment
