Answer:
√(4/5)
Step-by-step explanation:
First, let's use reflection property to find tan θ.
tan(-θ) = 1/2
-tan θ = 1/2
tan θ = -1/2
Since tan θ < 0 and sec θ > 0, θ must be in the fourth quadrant.
Now let's look at the problem we need to solve:
sin(5π/2 + θ)
Use angle sum formula:
sin(5π/2) cos θ + sin θ cos(5π/2)
Sine and cosine have periods of 2π, so:
sin(π/2) cos θ + sin θ cos(π/2)
Evaluate:
(1) cos θ + sin θ (0)
cos θ
We need to write this in terms of tan θ. We can use Pythagorean identity:
1 + tan² θ = sec² θ
1 + tan² θ = (1 / cos θ)²
±√(1 + tan² θ) = 1 / cos θ
cos θ = ±1 / √(1 + tan² θ)
Plugging in:
cos θ = ±1 / √(1 + (-1/2)²)
cos θ = ±1 / √(1 + 1/4)
cos θ = ±1 / √(5/4)
cos θ = ±√(4/5)
Since θ is in the fourth quadrant, cos θ > 0. So:
cos θ = √(4/5)
Or, written in proper form:
cos θ = (2√5) / 5
You just need to put (x+1) wherever you see x at.
y=(x+1)^3 + 2(x+1)^2 -5(x+1) -6
y= x^3 +1 +2x^2+2-5x-5-6
y=x^3+2x^2-5x -10
<h2>
Greetings!</h2>
Answer:
B)
Step-by-step explanation:
Y intercept:
Simply substitute all the x values with 0:
When x = 0:
3(0) - 2y = 18
Move the - 2y over to the other side making it a +2y:
0 = 18 + 2y
Move the +18 over to the other side making it a -18:
-18 = 2y
Divide both sides by 2:
-9 = y
So y intercept is:
<h3> (0 , -9)</h3>
X - intercept:
Simply substitute all the Y's with 0:
3x - 3(0) = 18
3x = 18
Divide both sides by 3:
x = 6
So the X intercept is:
<h3>(6 , 0)</h3>
This means that your guess of B is correct.
<h2>Hope this helps! </h2>
2x -1 is the answer I believe
