Answer:
$4742.10
Step-by-step explanation:
Exponential depreciation formula :-
, where y is the value of good after t years , r is rate of depreciation and A is the initial value.
Given : A= $20800 ; r=10.75%=0.1075
The equation models this situation:
Then, the value of car after t=13 years :-
Hence, the value of car after 13 years = $4742.10
Answer:
an= a1 +(n-1)*4
Step-by-step explanation:
a1 = 1, a2 =5, a3 = 9, a4= 13,... an= ?
we see that each term is getting bigger so usually that will happen because of addition or multiplication-in our case add 4 to previous term
a1 = 1,
a2 = a1+(2-1) 4 = 1+4 = 5,
a3 = a1 + (3-1)*4 = a1+8 = 1 + 8 = 9,
a4= a1 + (4-1)*4 = a1 + 12 = 1+12= 13,
...
an= a1 +(n-1)*4
Answer:
5^2x
Step-by-step explanation:
write the number in exponential form with a base of 5
(5^2)^x
simplify the expression by multiplying exponents
5^2x
1,327 days are in between 12/1/16 and 7/20/20
80x5,000 is 400,000. Not sure what you're asking though.
