If one gallon = 4 quarts
Then 5 gallons = x quarts
To solve this we can set up a porportion
1/4 = 5/x
To solve the porportion we need to find the rule so how to we get to 4 from 1? Well we can multiply 1 by 4 to get one right?
So if this is true, 1 x 4 = 4 then 5 x 4 must equal x
5 x 4 = 20 so the answer would be 20 quarts are in 5 gallons
Another way to look at this is that you have 5 gallons and in each gallon is 4 quarts to if there is 4 quarts in every one gallon then that’s just 4 + 4 + 4 + 4 + 4 or 5 x 4
I hope this helps! <3
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Answer: If we define 2:00pm as our 0 in time; then:
at t= 0. the velocity is 30 mi/h.
then at t = 10m (or 1/6 hours) the velocity is 50mi/h
Then, if we think in the "mean acceleration" as the slope between the two velocities, we can find the slope as:
a= (y2 - y1)/(x2 - x1) = (50 mi/h - 30 mi/h)/(1/6h - 0h) = 20*6mi/(h*h) = 120mi/
Now, this is the slope of the mean acceleration between t= 0h and t = 1/6h, then we can use the mean value theorem; who says that if F is a differentiable function on the interval (a,b), then exist at least one point c between a and b where F'(c) = (F(b) - F(a))/(b - a)
So if v is differentiable, then there is a time T between 0h and 1/6h where v(T) = 120mi/
Answer:
0.4
Step-by-step explanation:
15 = 5p - 13
-13 = 5p -13
---------------- ( subtract 13 on both sides )
<u> 2 = 5p</u>
5 = 5p
---------------- ( divide 2 by 5 )
p = 0.4
( p equals 0.4 )
I got the answer of 6127.731 hope this works out for you.
First of all, a positive average rate of change means that the function is increasing, so the answer can only be A->B or B->C.
The average rate of change is defined as
i.e. as the ratio between the vertical and horizontal gain.
In order to go from point A to point B, you gain 1 unit horizontally and 5 units vertically. So, the average rate of change is 5/1=5.
In order to go from point B to point C, you gain 1 unit horizontally and 3 units vertically. So, the average rate of change is 3/1=3.