Answer (4):
a=ub/k because
u=ak/b (starting equation)
ub=ak (multiply b to both sides)
a=ub/k (divide both sides by k)
Answer (6)
x=g+c-y because
g=x-c+y (starting equation)
x+y=g+c (add c to both sides)
x=g+c-y (subtract y from both sides)
Answer:
a) 25.15
b)
x = 1
y = t
z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)
c) (x,y) = (1, -2pi)
Step-by-step explanation:
a)
First lets calculate the velocity, that is, the derivative of c(t) with respect to t:
v(t) = (-sin(t), cos(t), 2t)
The velocity at t0=4pi is:
v(4pi) = (0, 1, 8pi)
And the speed will be:
s(4pi) = √(0^2+1^2+ (8pi)^2) = 25.15
b)
The tangent line to c(t) at t0 = 4pi has the parametric form:
(x,y,z) = c(4pi) + t*v(4pi)
Since
c(4pi) = (1, 0, (4pi)^2)
The tangent curve has the following components:
x = 1
y = t
z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)
c)
The intersection with the xy plane will occurr when z = 0
This happens at:
t1 = -2pi
Therefore, the intersection will occur at:
(x,y) = (1, -2pi)
8x^2 -3 = 2
add 3 to each side
8x^2 = 5
divide by 8
x^2 =5/8
take the square root of each side
x = +- sqrt (5/8)
Answer:
alternate exterior angles
Step-by-step explanation:
hope this helps
