Answer:
d = 5,35 ft
Step-by-step explanation: See annex
Figure in annex is clear,
sin ∠42⁰ = d / 8
And
sin ∠42⁰ = 0.669
d/8 = 0,669
d = 0,669*8
d = 5,35 ft
Answer:
approximation is often useful when it is not a very good one
Answer:
The large sample n = 190.44≅190
The large sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44
<u>Step-by-step explanation</u>:
Given population proportion was estimated to be 0.3
p = 0.3
Given maximum of error E = 0.04
we know that maximum error
The 85% confidence level
now calculation , we get
√n=13.80
now squaring on both sides n = 190.44
large sample n = 190.44≅190
<u>Conclusion</u>:-
Hence The large sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44
Answer:
The answer is: X= -1 and y= -2 so <em><u>(-1,-2)</u></em>
hope this helps
Answer:
The class width is 20
Step-by-step explanation:
In a frequency or a relative frequency distribution the class width is calculated as the difference between the lower or upper class limits of consecutive classes. A point to note is that all the categories or classes usually have the same class width.
We use the first two classes to calculate the class width by using their respective upper limits;
Class width = 89 - 69
Class width = 20