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2 years ago

Given f(x) = 1/3(4-x),What is the value of f(16)?

Mathematics

1 answer:

elena55 [62]2 years ago

3 0

Answer:

-1/4

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

16f=−4

Step 2: Divide both sides by 16.

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geniusboy [140]

Answer:

(2a, b )

Step-by-step explanation:

Given the endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

[ $\frac{1}{2}$ (x₁ + x₂ ), $\frac{1}{2}$ (y₁ + y₂ ) ]

Here (x₁, y₁ ) = N(2a, 2b) and (x₂, y₂ ) = P(2a, 0), thus

midpoint = [ $\frac{1}{2}$ (2a + 2a), $\frac{1}{2}$ (2b + 0 ) ] = (2a, b )

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2 years ago

Pears are $1.98 a pounds. How much do 3.5 pounds of Pears cost?

lina2011 [118]

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2 years ago

Find gradient xe^y + 4 ln y = x² at (1, 1)

cricket20 [7]

$xe^y+4\ln y=x^2$

Differentiate both sides with respect to x, assuming y = y(x).

$\dfrac{\mathrm d(xe^y+4\ln y)}{\mathrm dx}=\dfrac{\mathrm d(x^2)}{\mathrm dx}$

$\dfrac{\mathrm d(xe^y)}{\mathrm dx}+\dfrac{\mathrm d(4\ln y)}{\mathrm dx}=2x$

$\dfrac{\mathrm d(x)}{\mathrm dx}e^y+x\dfrac{\mathrm d(e^y)}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x$

$e^y+xe^y\dfrac{\mathrm dy}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x$

Solve for dy/dx :

$e^y+\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x$

$\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x-e^y$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x-e^y}{xe^y+\frac4y}$

If y ≠ 0, we can write

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2xy-ye^y}{xye^y+4}$

At the point (1, 1), the derivative is

$\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=1,y=1}=\boxed{\dfrac{2-e}{e+4}}$

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2 years ago

Evaluate the expression when a = 4 and b = 6. 8a – 4b + 5 A. 15 B. 7 C. 19 D. 13

yaroslaw [1]

4 and b = 6 is D.) 13

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3 years ago

Will give brainliest

ss7ja [257]

Answer:

Step-by-step explanation:

Base on the question where as asking to state the translation vectors could have been used for the pair of figures, base on my research, I would say that the answer would be arrow pointing to the right.

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2 years ago