The first problem is true because with multiplication it doesn't matter which order it is in.

The second problem is false because you will get a different quotient depending on which numbers are on which side of the equation.

3 0

2 years ago

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Can any one help me with this problem

Feliz [49]

Answer:

im so sorry but i havent learned this yet sorry

Step-by-step explanation:

3 0

3 years ago

Simplify (-3c^-3w^5)^3 A -9w^8 B. -27cw^8 C. w^15/27c^9 D.-27w^15/c^9

kenny6666 [7]

Answer:

$\large\boxed{D.\ \dfrac{-27w^{15}}{c^9}}$

Step-by-step explanation:

$(-3c^{-3}w^5)^3\qquad\text{use}\ (ab)^n=a^nb^n\\\\=(-3)^3(c^{-3})^3(w^5)^3\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=-27c^{-3\cdot3}w^{5\cdot3}=-27c^{-9}w^{15}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=-27\left(\dfrac{1}{c^9}\right)w^{15}=\dfrac{-27w^{15}}{c^9}$

4 0

2 years ago