6yd
8yd a =48sq yd (6×8=48)
4yd
12yd a=48sq yd (4×12=48)
Answer:
4x-y+1=0
Step-by-step explanation:
here,given equation of a line id
4x-y-2=0.. eqn(i)
equation of any line parallel to line (i) is
4x-y+k=0...eqn(ii)
since, the line(ii) passes through (1,5)[replacing x=1 and y=5 in eqn(ii), we get]
4*1-5+k=0
or, 4-5+k=0
or,-1+k=0
•°•k=1
substituting the value of k=1 in eqn(ii),
4x-y+1=0 is the required equation of the line.
Answer:
k12
Step-by-step explanation:
Step-by-step explanation:
We have been given that AE=BE and .
We can see that angle CEA is vertical angle of angle DEB, therefore, as vertical angles are congruent.
We can see in triangles CEA and DEF that two angles and included sides are congruent.
or
Therefore, by ASA postulate.
Since corresponding parts of congruent triangles are congruent, therefore CE must be congruent to DE.