Two rectangles have the same area of 70m2. It is given that the length of the first rectangle is 4m longer and the width is 2m s
horter than the dimensions of the second rectangle. Find the lengths of the sides of these rectangles.
1 answer:
Answer:
second rectangle
longer = 10
width = 7
first rectangle
longer = 14
width= 5
Step-by-step explanation:
You might be interested in
(1 7/10) / (3/5)
(17/10) / (3/5) =
17/10 * 5/3 =
85/30 =
2 5/6........yes, because 1 7/10 divided by 3/5 = 2 5/6...answer C
1 2 4 8 16 32 64 128 256 512 1024. each one is 2 times the previous
Answer:
0
Step-by-step explanation:
−2−(−4)−2
=2−2
=0
Answer:
00.29
Step-by-step explanation:
