We know that
<span>the regular hexagon can be divided into 6 equilateral triangles
</span>
area of one equilateral triangle=s²*√3/4
for s=3 in
area of one equilateral triangle=9*√3/4 in²
area of a circle=pi*r²
in this problem the radius is equal to the side of a regular hexagon
r=3 in
area of the circle=pi*3²-----> 9*pi in²
we divide that area into 6 equal parts------> 9*pi/6----> 3*pi/2 in²
the area of a segment formed by a side of the hexagon and the circle is equal to <span>1/6 of the area of the circle minus the area of 1 equilateral triangle
</span>so
[ (3/2)*pi in²-(9/4)*√3 in²]
the answer is
[ (3/2)*pi in²-(9/4)*√3 in²]
Answer:
30
Step-by-step explanation:
Answer:
16/81
Step-by-step explanation:
(2/3)^4 = (2/3)*(2/3)*(2/3)*(2/3)
= 16/81
Answer:
907120
Step-by-step explanation:
Answer:
3
Step-by-step explanation:
3 is positive and -2.5 is negative 2 is greater than 2.50 so the answer is 3
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