The minimum distance is the perpendicular distance. So establish the distance from the origin to the line using the distance formula.
The distance here is: <span><span>d2</span>=(x−0<span>)^2</span>+(y−0<span>)^2
</span> =<span>x^2</span>+<span>y^2
</span></span>
To minimize this function d^2 subject to the constraint, <span>2x+y−10=0
</span>If we substitute, the y-values the distance function can take will be related to the x-values by the line:<span>y=10−2x
</span>You can substitute this in for y in the distance function and take the derivative:
<span>d=sqrt [<span><span><span>x2</span>+(10−2x<span>)^2]
</span></span></span></span>
d′=1/2 (5x2−40x+100)^(−1/2) (10x−40)<span>
</span>Setting the derivative to zero to find optimal x,
<span><span>d′</span>=0→10x−40=0→x=4
</span>
This will be the x-value on the line such that the distance between the origin and line will be EITHER a maximum or minimum (technically, it should be checked afterward).
For x = 4, the corresponding y-value is found from the equation of the line (since we need the corresponding y-value on the line for this x-value).
Then y = 10 - 2(4) = 2.
So the point, P, is (4,2).
Step-by-step explanation:
If we let the width be w, then the length is w+3.5.
This means that w(w+3.5)=11
w^2 + 3.5w - 11 = 0
2w^2 + 7w - 22 = 0 (multiply both sides by 2)
(2w+11)(w-2)=0
w = -11/2 or w = 2 (disregard w = -11/2 as distance is positive)
This means that w=2, and thus the length is 2+3.5=5.5
Answer:
20xp
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given polynomial is (-10x + 1).
This polynomial has two terms.
Therefore, it's a binomial with two separate terms.
The expression represents a binomial polynomial with two terms. The constant term is 1, the leading term is -10x, and the leading coefficient is (-10).
Answer:
Thank you
Step-by-step explanation:
Have a great day :D
