If only 0.225 g of Ca(OH)2 dissolves in enough water to give 0.100 L of aqueous solution at a given temperature, what is the Ksp
Answer: The value for calcium hydroxide at this temperature is .
Explanation:
Given: Mass of = 0.225 g
Volume = 0.100 L
As moles is the mass of substance divided by its molar mass.
So, moles of (molar mass = 74 g/mol) is calculated as follows.
Molarity is the number of moles of substance present in a liter of solution.
Hence, molarity of given solution will be as follows.
The equation for dissociation of is as follows.
This means that and . Hence, value for this reaction is calculated as follows.
Thus, we can conclude that the value for calcium hydroxide at this temperature is .
Answer:
Digestion take place in Fats.
Answer:
MgCO₃
Explanation:
From the question given above, we obtained:
MgF₂ + Li₂CO₃ —> __ + 2LiF
The missing part of the equation can be obtained by writing the ionic equation for the reaction between MgF₂ and Li₂CO₃. This is illustrated below:
MgF₂ (aq) —> Mg²⁺ + 2F¯
Li₂CO₃ (aq) —> 2Li⁺ + CO₃²¯
MgF₂ + Li₂CO₃ —>
Mg²⁺ + 2F¯ + 2Li⁺ + CO₃²¯ —> Mg²⁺CO₃²¯ + 2Li⁺F¯
MgF₂ + Li₂CO₃ —> MgCO₃ + 2LiF
Now, we share compare the above equation with the one given in the question above to obtain the missing part. This is illustrated below:
MgF₂ + Li₂CO₃ —> __ + 2LiF
MgF₂ + Li₂CO₃ —> MgCO₃ + 2LiF
Therefore, the missing part of the equation is MgCO₃
That is what I think anyways :)
Explanation:
Mass = volume × density
Mass = 652 cm³ × 21.45 g/cm³
= 13985.4 g
Explanation: