The y-intercept of linear function (f- g)(x) is (0,9)
<h3>How to determine the y-intercept?</h3>
The table of values is given as:
x -6 -4 -1 3 4
f(x) 15 11 5 -3 -5
g(x) -36 -26 -11 9 14
The equations of the functions is calculated using:
So, we have:
Evaluate
f(x) = -2x + 3
Also, we have:
Evaluate
g(x) = 5x - 6
Next, we calculate (f - g)(x) using:
(f - g)(x) = f(x) - g(x)
This gives
(f - g)(x) = -2x + 3 - 5x + 6
Substitute 0 for x
(f - g)(0) = -2(0) + 3 - 5(0) + 6
Evaluate
(f - g)(0) = 9
Hence, the y-intercept of (f- g)(x) is (0,9)
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Answer:
Step-by-step explanation:
That '5' in f(5x) will compress the graph of x^2 horizontally.
If you were to graph f(x) = x^2, you'd get a parabolic graph; the parabola will open UP.
Suppose you graphed f(x) = x^2 on the interval [-4, 4].
Then the graph of g(x) = f(5x) would be graphed on the interval [-4/5, 4/5]. In other words, the graph would be on a shorter interval, one shorter by a factor of 5.
Given parameters;
Let us solve this problem step by step;
Let us represent Simon's money by S
Kande's money by K
- Simon has more money than Kande
S > K
- if Simon gave Kande K20, they would have the same amount;
if Simon gives $20, his money will be S - 20 lesser;
When Kande receives $20, his money will increase to K + 20
S - 20 = K + 20 ------ (i)
- While if Kande gave Simon $22, Simon would then have twice as much as Kande;
if Kande gave Simon $22, his money will be K - 22
Simon's money, S + 22;
S + 22 = 2(K - 22) ------ (ii)
Now we have set up two equations, let us solve;
S - 20 = K + 20 ---- i
S + 22 = 2(K - 22) ; S + 22 = 2K - 44 ---- ii
So, S - 20 = K + 20
S + 22 = 2K - 44
subtract both equations;
-20 - 22 = (k -2k) + 64
-42 = -k + 64
k = 106
Using equation i, let us find S;
S - 20 = K + 20
S - 20 = 106 + 20
S = 106 + 20 + 20 = 146
Therefore, Kande has $106 and Simon has $146
85.25 would be one thenth of 8.524
Answer:
c) 3x - 45 = 10
Step-by-step explanation:
Cross multiply,
3*(x - 15) = 2*5
3*x - 3*15 = 10
3x - 45 = 10
