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2 years ago

Anyone who wants to ask me any questions directly can type it here! I will help as much as i can.

Mathematics

1 answer:

Sergio039 [100]2 years ago

6 0

Can you help me with this please

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Caroline walks around a square pond with 30 m sides. Her paces are about 60 cm long. About how many paces will she take?

Elza [17]

Step-by-step explanation:

Perimeter of a square = 4 × L

L = Length of a side of the pond = 30m

Perimeter = 4 × L = 4 × 30 = 120m = 12,000 cm

Pace = 60cm

Number of paces = 12,000/60 = 200 paces

3 0

2 years ago

PLEASE HELP URGENT!!! 30 POINTS TO WHOEVER ANSWERS BOTH QUESTIONS!!

Alex Ar [27]

This isn’t 30 points this is 15

3 0

2 years ago

Use the table from a random survey about the preferred service for streaming movies. Out of 750 people, how many would you expec

LiRa [457]

Answer:

The correct answer option is 192

Step-by-step explanation:

We are given the results of a random survey about the preferred service for streaming movies.

We are to find the number of people we would expect to prefer Company B.

Number of people using service B = 32

Total number of people = 125

Number of people expected to prefer Company B =32/125 x 750 = 192

3 0

1 year ago

Work out the angle of elevation from the

insens350 [35]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \:Angle \:\: of \:\: elevation= 30°$

____________________________________

$\large \tt Solution \: :$

Let the angle of elevation be " x "

$\qquad \tt \rightarrow \: \cos(x) = \dfrac{9 \sqrt{3} }{18}$

$\qquad \tt \rightarrow \: \cos(x) = \dfrac{ \sqrt{3} }{2}$

$\qquad \tt \rightarrow \: x = \cos {}^{ - 1} \bigg( \cfrac{ \sqrt{3} }{2} \bigg )$

$\qquad \tt \rightarrow \: x = 30 \degree \: \: or \: \: \cfrac{ \pi}{6} \: \: rad$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

8 0

1 year ago

Read 2 more answers

You are researching two glaciers.the first glacier flows at a rate of 75 meters in 3 days.the second glacier flows at a rate of

podryga [215]

Answer:

$1.3\ days$

Step-by-step explanation:

step 1

Find the units rate of the first glacier

$\frac{75}{3}=25\frac{meters}{day}$

using proportion

$\frac{25}{1}\frac{meters}{day}=\frac{200}{x}\frac{meters}{days}\\ \\x=200/25\\ \\x=8\ days$

step 2

Find the units rate of the second glacier

$\frac{107.5}{5}=21.5\frac{meters}{day}$

using proportion

$\frac{21.5}{1}\frac{meters}{day}=\frac{200}{x}\frac{meters}{days}\\ \\x=200/21.5\\ \\x=9.3\ days$

step 3

Find the difference

$9.3\ days-8\ days=1.3\ days$

4 0

2 years ago